FTalk

flint_hydz wrote:

matagal na akong di nka C++. wew..
*nosebleed*

Wow. very good. didn't expected that you'd answer it by C++ (though it's for C), haha. Well anyway, i'm quite amazed, 'cause i'm not really that familiar with C++ functions, i'm more used to C. But your answer is definitely correct. Though our codes are different, the output was the same.

flint_hydz wrote:

I don't know function prototype

I wanted to give you a sample of this program, but i reformatted my laptop and forgot to back up my C++ sample programs. I haven't saved any in the net so I have to redo all of these again.


Anyway, Hope u could answer #3 soon!! Gudluck.

Last edited by othe_89 (2009-09-30 16:39:08)

For your #1:

dhenzbhee wrote:

#include <stdio.h>
#include <conio.h>

main()
{
  clrscr();
  int num, rem;
  printf("ENTER A NUMBER: ");
  scanf("%d", &num);

  rem = num % 2;

  if (rem == 0)
    printf("NOT PRIME");
  else
    printf("PRIME");

  getch();

}

This, my friend, is wrong. I tried running your program and it modified 1,15,25 and some other numbers as prime numbers, but they are not. Actually, the list of prime numbers are:

For your #4:

dhenzbhee wrote:

#include<stdio.h>
#include<conio.h>

main()
{
    char ans;

    do
    {

    clrscr();
    int num;

    printf("Guess a number [1-10]");
    scanf("%d",&num);

    if (num==4)
        printf("CORRECT!");
    if (((num>=1)&(num<4)) || ((num>4)&(num<=10)))
        printf("INCORRECT!");
    if ((num>10) || (num<1))
        printf("OUT OF RANGE!");




    printf("\n\nDo you want to try Another?[Y/N]");
    scanf("%s",&ans);
    } while((ans=='Y')||(ans=='y'));

    getch();
}

This, again, is wrong. The program didn't randomize the said numbers but actually, only focused on the "4" number as the Correct one. The program should randomly choose a number between 1 and 10. And the user should type in the number of his guess. So if the user kept on choosing the same number over and over again, he should get either Correct or Incorrect message spontaneously. In your program, number 4 was the only one correct and the rest were not. You only need the code for randomization and you can get this done next time.


For your #5:

dhenzbhee wrote:

#include <stdio.h>
#include <conio.h>

main()

{
    char ans;

    do
    {

    clrscr();
    int n, i, x, a, b;

    printf("Enter a number: ");
    scanf("%d", &n);

      a = x = 1;
      printf("\nFibonacci series:");
      for (i=1; i<=n; i++)
      {
    printf(" %d",x);
    b = x+a;
    x = a;
    a = b;
      }
      printf("\n\nDo you want to try another?[Y/N]");
      scanf("%s",&ans);

      } while((ans=='Y')||(ans=='y'));
      getch();
}

This one is correct. Very clear and detailed. Your code is understandable and more simplier than mine actually . Congrats.

Over all. You got 1 correct program out of 3.  Hope you get the rest. Keep it up.

dhenzbhee wrote:

but sir othe_89, you did not mention on your problem no. 4 that the correct number should be picked randomize, so i assumed that i will assign my own number. i just did what's on your problem #4 which is to...

Sorry abt that Mr. dhenzbhee, my bad. You simply misunderstood my given exercise. I should have mentioned that the program should be randomized from numbers 1-10. Perhaps i should reedit it.

dhenzbhee wrote:

#include<stdio.h>
#include<conio.h>
#include<time.h>
#include<stdlib.h>

main()
{
    char ans;

    do
    {

    clrscr();
    int num, i;

    randomize();

    printf("Guess a number [1-10]");
    scanf("%d",&num);

    i = rand() % 11;

    if (num==i)
        printf("CORRECT!");
    if ((num!=i) && ((num>=0 && num<=10)))
        printf("INCORRECT!");
    if (num>10)
        printf("OUT OF RANGE!");


    printf("\n\nDo you want to try Another?[Y/N]");
    scanf("%s",&ans);
    } while((ans=='Y')||(ans=='y'));

    getch();
}

Still wrong. You included 0 (zero) to be randomized. Your out of range digits should be less than 1 and/or greater than 10. You should reedit your if-else statement to make it right.

dhenzbhee wrote:

on example #1, my mistake, i thought prime # and not prime # is the same as odd and even.

Haha. i think this one will be quite easy for you to redo now that you have #5 done.




Anyway, tnx for participating Mr. dhenzbhee.

dhenzbhee wrote:

#include<stdio.h>
#include<conio.h>
#include<time.h>
#include<stdlib.h>

main()
{
    char ans;

    do
    {

    clrscr();
    int num, i;

    randomize();

    printf("Guess a number [1-10]");
    scanf("%d",&num);

    i = rand() % 10 + 1;

    if (num==i)
        printf("CORRECT!");
    if ((num!=i) && ((num>=1 && num<=10)))
        printf("INCORRECT!");
    if ((num>10) || (num<1))
        printf("OUT OF RANGE!");


    printf("\n\nDo you want to try Another?[Y/N]");
    scanf("%s",&ans);
    } while((ans=='Y')||(ans=='y'));

    getch();
}

Now you've got it right. Great.
Now i have to make some more exercises.

Well anyway, how about, making this program without any kind of loop? But can run the program again to the start (without exiting) after selecting 'y'/'Y' in the "Try Again" question. 

i forgot 'bout that C++, anyway I enjoyed the DELAY SCRIPT and text colors and blinking effects...

^ Lol. Ok, Ignore the commas.. a space will do, i just want to see the even and the odd numbers being separated.

flint_hydz wrote:

- Example Output -

Enter a number :
1
2
3
4
5
6
7

The odd numbers are : 1, 3, 5, 7
The even numbers are : 2, 4, 6

i think i got the program with a comma in it. But it seems more complicated than with spaces only.

#include<stdio.h>
#include<conio.h>
main()
{
int a,b,c,d=0,e=0,f=1,num[49];


    clrscr();
    printf("Enter number(s): \n");

    for(b=0;b<50;b++)
        {

        scanf("%d",&num[b]);
        if(num[b]==0)
            {

            c=b;
            b=50;
            }

         }


    for(a=0;a<c;a++)
        {

        if(num[a]%2==0)
        {d=a+1;}
        if(num[a]%2!=0)
        {e=a+1;}

        }d--;;e--;

    printf("\n\nEven Numbers are: ");

    for(a=0;a<c;a++&&f++)
        {


        if(num[a]%2==0&&num[a]!=0)
            {

            printf("%d",num[a]);
            if(c<3&&a<1)
            printf(",");

            }
        if(f<d&&num[a]%2==0)
            {printf(",");}


        }

    f=1;
    printf("\n\nOdd Numbers are: ");
    for(a=0;a<c;a++&&f++)
        {

        if(num[a]%2!=0)
            {
            printf("%d",num[a]);
            if(c<3&&a<1)
            printf(",");
            }
        if(f<e&&num[a]%2!=0)
            {printf(",");}

        }


getch();clrscr();return 0;
}

Envy you people! Hopefully I would become as good as you do.